#!/usr/bin/env bash
set -euo pipefail

IMG=/home/jm/Downloads/receipt.jpeg
B64=$(base64 -w0 "$IMG")

OUT=response.json

curl -s https://api.anthropic.com/v1/messages \
  -H "x-api-key: $CLAUDE_API_KEY" \
  -H "anthropic-version: 2023-06-01" \
  -H "content-type: application/json" \
  -o "$OUT" \
  -d @- <<EOF
{
  "model": "claude-opus-4-8",
  "max_tokens": 1024,
  "messages": [
    {
      "role": "user",
      "content": [
        {
          "type": "image",
          "source": { "type": "base64", "media_type": "image/jpeg", "data": "$B64" }
        },
        {
          "type": "text",
          "text": "Analyze this receipt and return ONLY a JSON object, no prose, with these fields:\n- \"person\": one of exactly \"jean-michel tremblay\", \"lynna nguyen\", or \"could not fetch\" if the name is absent or matches neither. The first and last name may appear in any order (e.g. \"Tremblay Jean-Michel\" or \"Nguyen, Lynna\"), possibly with a middle initial or accents; match on the name regardless of order or formatting.\n- \"category\": one of exactly \"pharmacy\", \"dental\", \"medical\", or \"other\".\n- \"date\": the receipt date as YYYY-MM-DD, or \"could not fetch\". Today is 2026-06-12, and the receipt date is usually within the last year or two of that (it may be a backfilled older receipt). The year is the last component; if it is only two digits, expand it to a year near the present (20YY within about 2 years of today), never far in the past or future. This is a US receipt, so read ambiguous numeric dates as MM-DD-YY.\n- \"amount\": the total as a plain number string (e.g. \"42.50\"), or \"could not fetch\"."
        }
      ]
    }
  ]
}
EOF

echo "Raw response saved to $OUT"
jq -r '.content[0].text' "$OUT"

# Cost — Opus 4.8: $5/M input, $25/M output
jq -r '
  .usage as $u
  | ($u.input_tokens // 0) as $in
  | ($u.output_tokens // 0) as $out
  | ($in * 5 / 1000000) as $cin
  | ($out * 25 / 1000000) as $cout
  | "\n--- usage ---\ninput:  \($in) tok  $\($cin * 10000 | round / 10000)\noutput: \($out) tok  $\($cout * 10000 | round / 10000)\ntotal:  $\(($cin + $cout) * 10000 | round / 10000)"
' "$OUT"